-1=-0.25x^2+3x

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Solution for -1=-0.25x^2+3x equation:



-1=-0.25x^2+3x
We move all terms to the left:
-1-(-0.25x^2+3x)=0
We get rid of parentheses
0.25x^2-3x-1=0
a = 0.25; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·0.25·(-1)
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{10}}{2*0.25}=\frac{3-\sqrt{10}}{0.5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{10}}{2*0.25}=\frac{3+\sqrt{10}}{0.5} $

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